We can use perpendicular gradients to find the value of \(m\), then use the coordinates of P to find the value of \(c\) in the equation. Find the equation of the tangent to the circle \(x^2 + y^2 ...

Any point P with coordinates (\(x ... This means that, using Pythagoras’ theorem, the equation of a circle with radius r and centre (0, 0) is given by the formula \(x^2 + y^2 = r^2\).