2012年5月3日 · One of the formulas I came across while doing problems with simple parallel plate capacitors was E = V/d, where E is the magnitude of the electric field between the plates, V is the potential difference between the plates, and d is the separation of …

2021年11月12日 · Determine the direction and magnitude of the electric field at a point P lying a distance ##x>0## from the center of the disc along the axis of symmetry of the disc. Relevant Equations I know how to solve this problem. The electric field vector points in only one direction, so there is really only one integral to do.

2008年2月10日 · A long glass filament carries a charge density [tex]\lambda = - 2.7{\rm{ nC/m}}[/tex] . What is the magnitude of the electric field 0.67 mm from the filament? The Attempt at a Solution Did I do this problem correctly? I'm guessing not because my answer has an extra /m . Shouldn't it simply be N/C? [tex]

2014年2月20日 · To calculate the electric field for a capacitor, you can use the formula E = V/d or E = λ/2πεr, depending on the type of capacitor. Simply plug in the values for potential difference, distance/charge density, and permittivity/radius to get the electric field strength.

2010年8月23日 · Solve for the charge density given your original voltage (400 KV) and then substitute back into the electric field equation to find the actual fields. Of course though, for the specific question of the electric field strength at the ground it will be zero. But I have a feeling that there are a myriad of books that deal with the above problems.

2012年8月18日 · Homework Statement A proton (+e) accelerates from rest in a uniform electric field of 640 N/C. At some later time, the proton's speed is 1.20 x 10^6 m/s. Find the acceleration of the proton. The mass of a proton is 1.67x10^-27 kg. Charge on a proton is +1.6x10^-19C. Homework Equations...

2004年5月16日 · the mass of the electron is 9.1x10^-31 kg and its charge is -1.6x10^-19 c. Calculate the acceleration of an electron that is in a constant electrin field who intensity is 5.10x10^2 N/C upwards. (answer according to back: 9x10^13 m/s^2 (down)) thank you …

2012年7月4日 · Consider an insulating sphere of radius R centered on the origin with total charge Q uniformly distributed throughout the volume of the sphere. What is the electric field E inside the sphere at a distance r from the origin? (i.e. r<R) Homework Equations They list Vshpere=4/3 ∏r^3 and Asphere=4∏r^2 I know E=kQ/r^2=f/q The Attempt at a Solution

2015年6月17日 · Physics news on Phys.org . Greetings from the fourth dimension: Scientists glimpse 4D crystal structure using surface wave patterns

2019年4月11日 · The electric field in point A due to the cube with side a and with uniform volumetric charge density is E. What is the electric field at point A when a cube of side a/2 is taken out from the original cube, such as in the picture. Relevant Equations E=kq/r^2