How to integrate arc sin x dx? - Socratic
2016年3月4日 · intarcsin(x)dx = xarcsin(x)+sqrt(1-x^2)+C We will proceed by using integration by substitution and integration by parts. Substitution: Let t = arcsin(x) => x = sin(t) and dx = cos(t)dt Then, substituting, we have intarcsin(x)dx = inttcos(t)dt Integration by Parts: Let u = t and dv = cos(t)dt Then du = dt and v = sin(t) By the integration by parts formula intudv = uv - intvdu …
Evaluate $\\int x \\arcsin(x)dx$. - Mathematics Stack Exchange
2021年1月24日 · Evaluate: $$\int x \arcsin(x)dx$$ My first guess was $u$ substitution but that didn't get me very far. I think using integration by parts is the correct way.
integral of $\\arcsin(\\sin(x))$ - Mathematics Stack Exchange
integral of $\arcsin(\sin(x))$ Ask Question Asked 14 years ago. Modified 6 years, 1 month ago. Viewed 4k ...
integration - Integral of $\,\arcsin (x)/ (x^2)$ - Mathematics Stack ...
2018年1月24日 · Integral of $\,\arcsin(x)/(x^2)$ Ask Question Asked 6 years, 10 months ago. Modified 1 year, 11 months ago ...
Evaluate $\\int (\\arcsin(x))^2 dx$ - Mathematics Stack Exchange
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integration - Help with the Integral of $x \arcsin x\,dx
2017年4月22日 · So I've started the integration using integration by parts, but I'm stuck on the second part of it. $$ \int_0^\frac{1}{2} x \sin^{-1}x dx $$ Step 1.
How do you find the integral of #int [arcsin(x)]^n# if is an
2015年9月28日 · How do I evaluate the indefinite integral #int(tan^2(x)+tan^4(x))^2dx# ? How do I evaluate the indefinite integral #intx*sin(x)*tan(x)dx# ? See all questions in Integrals of Trigonometric Functions
integration - $\int \arcsin\sqrt{1-x^2} dx$ - how to evaluate ...
2020年5月2日 · I've been trying to solve this integral $$ \int \arcsin\sqrt{1-x^2}\, dx, $$ but got an expression with an ...
calculus - Integral of $\int{\frac{dx}{(\arcsin{x})\sqrt{1-x^2 ...
But here, experience will let you recognize $\frac{1}{\sqrt{1-x^2}}$ as the derivative of $\arcsin x$, and if you notice that the only thing left over is an expression of $\arcsin x$, then that should suggest trying a substitution. $\endgroup$
integration - How to evaluate $\int \sin (x)\arcsin (x)dx ...
From the comments, there seems to be "no closed form in terms of standard functions" (to quote Simon S).Also, you have to be careful that the domains of the two functions are not the same: $\sin(x)$ takes values from $\mathbb{R}$, but the domain of $\arcsin(x)$ is restricted to $[-1,1]$.