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Deriving the derivative formula for arcsecant correctly
2015年9月24日 · "For, if y = arcsec x, then the angle y falls either in the first or second quadrants. When angle y falls in the first quadrant, then both sec y and tan y are positive. Therefore their …
What is the derivative of #y="arcsec"(x)#? - Socratic
2018年5月19日 · What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions
Why the derivative of inverse secant has an absolute value?
2020年6月27日 · So if you define the arc secant function on $(-\infty,-1] \cup [1,\infty)$ so that its range is $\left[0,\frac\pi2\right) \cup \left(\frac\pi2,\pi\right]$ then $$ …
What is the derivative of this function #arcsec(x^3)#? - Socratic
2017年11月16日 · For this you need to know what the derivative of arcsec(x) is. You can derive it fairly easily: #y ...
How do you find the derivative #g(x)=arcsec(2x)#? - Socratic
2017年12月29日 · How do you find the derivative #g(x)=arcsec(2x)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer
calculus - Definition of $\operatorname {arcsec} (x)
2016年2月25日 · My calculus book gives for the derivative of $\operatorname{arcsec}(x)$: $$\frac{d}{dx} \sec^{-1}x=\frac{1}{|x|\sqrt{x^2-1}}$$ Then it continues to state that: "Some …
calculus - Derivative of $\operatorname{arcsec } x$ using first ...
2017年5月2日 · P.S. The original question asked for the derivative of $\sqrt{\arcsec x}$; I managed to bring it till here after multiplying the denominator and numerator by conjugate of …
How do you find the derivative of the function: #arcsec(x/2)
2016年5月2日 · How do you find the derivative of the function: #arcsec(x/2)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions
What is the derivative of #"arcsec"(e^(2x))#? - Socratic
2018年5月19日 · What is the derivative of #"arcsec"(e^(2x))#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer
How do you find the derivative of #y = sec^(-1)(x/3)#? - Socratic
2015年8月22日 · A quick word about why the derivative of #"arcsec"(x)# uses the absolute value of #x#. The idea is that when you use implicit differentiation to find the derivative of …