2021年12月15日 · Is this the correct part in the manual for the calculation of the uncertainty in the voltage measurement? If so is the following the correct way to calculate the uncertainty for a 72mV/div and a reading of 10mv and with an average acquisition mode greater than 16 Waveforms: 0.03 * 0.01V + 0.1 * 0.072 V+0.001V = 0.009 V (with rounding up)

2019年1月11日 · A recent question asks students to calculate the total resistance of parallel resistors R 1 and R 2 with uncertainty. R 1 = 120 Ω (+/-10%). R 2 = 500 Ω (+/-10%).

2020年10月14日 · My teacher tells us that this is the statistical version of uncertainty that gives us 68 percent of the total uncertainty. I am having a hard time with this definition. It seems if this were true we could just multiply the equation given earlier by 0.68.

2018年5月23日 · Error/uncertainty interval goes negative while the value is known to be positive, how to report the interval? 0 Has my textbook given the incorrect equation for calculating uncertainty in multiplication?

2017年9月15日 · Calculate the uncertainty in velocity of an electron. By simple calculations one can see that the answer would be $5.79 \times 10^{10} m/s$ What does the uncertainty greater than light logically mean [?] This means that the uncertainty in the velocity of an electron is 193x greater than the speed of light, not the velocity of the electron.

2018年10月4日 · But when I go and calculate the minimum I just can't get the result 196 which would be 4 lower than 200. That's because first rule is forcing me to have 2 significant figures in the result so 196.02 is round up to $\color{red}{20\cdot 10^1}$ and not 196 which I need.

However, for each of the times there is an uncertainty of between 0.08 and 0.09 seconds. So, I asked my teacher for assistance and he explained the following: First you remove the 0.303, and then you can rearrange it as follows:

2019年6月8日 · I needed to find the uncertainty of a wavelength using Heisenberg's uncertainty principle. In the solution, they differentiated $λ=c/f$ with respect to frequency to get $\frac{-c}{f^{2}}$. λ is then substituted back in to get $\frac{- λ^{2}}{c}$. $Δf$ had already been found, so the final equation to find $Δλ$ was:

2021年10月29日 · As per a comment made by Mark H. for very small angles, the computed uncertainty will be large (since the the expression for $\Delta\phi$ becomes large if the denominator approaches zero) so an additional term to the $|\Delta \cos(\phi )|$ expression is added so that we now have the equation (Taylor series expansion about $\phi\approx 0 ...

2021年5月5日 · The square of the uncertainty of the momentum is $$\sigma_p^2 = \langle p^2 \rangle - \langle p \rangle ^2.$$ From the reading I have done, it seems that $\langle p^2 \rangle$ is calculated as