How would you balance Na(s) + Cl2 → NaCl(s)? - Socratic
2015年10月18日 · The balanced equation is "2Na(s)"+"Cl"_2("g")"rarr"2NaCl(s)". How to Balance the Equation "Na(s)"+"Cl"_2("g")"rarr"NaCl". Since there are two chlorine atoms on the left side, there needs to be two chlorine atoms on the right side. So I put a coefficient of two in front of the formula "NaCl". "Na(s)"+"Cl"_2("g")"rarr"2NaCl" Now there are two sodium and two chlorine …
In the reaction 2Na + Cl2 --> 2NaCl Would 2Na be the ... - Socratic
2018年4月14日 · Just Na. We have the balanced equation: 2Na(s)+Cl_2(g)->2NaCl(s) Na(0) gets oxidized to Na(I), while Cl(0) gets reduced to Cl(-I). Since sodium got oxidized, it is the reducing agent in this equation. It doesn't matter if there was one sodium or three sodium atoms, the reducing agent is just the element or molecule itself, so Na will be the reducing agent here.
Cl_2 -> 2NaCl# is an example of which type of reaction? - Socratic
2017年1月28日 · The reaction you have here #2"Na"_ ((s)) + "Cl"_ (2(g)) -> 2"NaCl"_ ((s))# is an example of a synthesis reaction.
Na + Cl2 --> 2 NaCl If 15 mol Na reacts with 15 mol Cl2 ... - Socratic
2018年2月25日 · You forgot to balance the equation for each mol of Cl_2, 2 mols of Na react, so therefore Na is limiting and Cl_2 is excess Check for LR 15 mol Cl_2 *(2mol Na)/ (1 mol Cl_2) Therefore 30 mol Na will be required to react, and since we don't have that amount, Na is limiting.
What is the equation for sodium and chlorine react to form …
2017年3月14日 · 2Na + Cl_2 -> 2NaCl The skeletal equation: Na + Cl_2 -> NaCl Balanced: 2Na + Cl_2 -> 2NaCl
Sodium and chlorine react to form sodium chloride: 2Na (s
2017年6月15日 · Sodium and chlorine react to form sodium chloride: 2Na (s) + Cl2 (g) ----> 2NaCl (s) For the reaction of 44.0g Na with 69.9 g Cl2, what is the limiting reactant and what is the theoretical yield of sodium chloride in grams?
For the reaction 2NaI + Cl2 →2NaCl + I2 How many grams of
2018年3月12日 · 0.97528 \\ "g"~~1 \\ "g" We have the balanced equation (without state symbols), as 2NaI+Cl_2->2NaCl+I_2 What I first try to do is to find the limiting reactant with these types of problems, so let's do that first. NaI has a molar mass of 149.89 \\ "g/mol", so 2NaI has a molar mass of 149.89*2=299.78 \\ "g/mol". An average Cl atom has a molar mass of 35.453 \\ …
A chemist performs the synthesis of sodium chloride from its
2016年4月16日 · We have 2 mol of sodium metal to start; clearly we need the 1 mole of Cl_2(g). "Moles of sodium "=(46.0*g)/(22.9*g*mol^-1)=2*mol. Given your equation, clearly we need the ONE mole of Cl_2 gas. What is the mass of this quantity of chlorine? It is fact that all of the elemental gases EXCEPT for the Noble Gases are diatomic: N_2, O_2, F_2, Cl_2. Of course, …
How many moles of chlorine gas (Cl2) would react with 5
2015年11月4日 · "2.5 mol Cl"_2" will react with "5 mol Na". Balanced Equation "2Na(s)" + "Cl"_2("g")rarr"2NaCl(s)" Multiply the given moles of "Na" times the mole ratio (1"mol Cl"_2 ...
For the reaction 2Na (s) + Cl_2 (g) - Socratic
2017年1月28日 · 67,9 g You have to search the limiting reagent between Na and Cl_2 You have n= "mass"/"molecular mass" = (103,0 g)/(23,0 (g/(mol))) = 4,47 mol of Na. As 1 mole occupies 22,4 L at STP you have n= (13,0L)/(22,4(L/(mol))) = 0,580 mol of Cl_2 The limiting reagent is Cl_2. since from the balanced reaction you have 2 mol of NaCl from one of Cl_2, making the …