Use the HAVING clause and GROUP By the fields that make the row unique. The below will find. all users that have more than one payment per day with the same account number. SELECT user_id, COUNT(*) count FROM PAYMENT GROUP BY …

2012年6月1日 · SQL count occurence of having count > 2 with condition. 1. combination of having count and column query. 4 ...

2010年9月22日 · Using COUNT with a GROUP BY clause will provide a count for each group. If you want the count of the number of groups, it will have to be a separate query (like your CTE example). I would just use a simple subquery, instead of the CTE:

2022年9月25日 · The HAVING clause is used with COUNT()instead of a WHERE clause. Now see the below example, I have used simple data and ordered it to help with the explanation. You have the below query and are applying to the table TeamMember. SELECT FirstName,COUNT(*) FROM TeamMember GROUP BY FirstName HAVING COUNT(*)>3 TeamMember

SELECT name, email, COUNT(*) AS Occurence FROM NewTable GROUP BY name, email HAVING COUNT(*) > 1 The GROUP BY clause groups the rows into groups by values in both name and email columns. Then, the COUNT() function returns the number of occurrences of each group (name,email).

2013年1月9日 · I want the name of the playlist and the count() for the songs displayed. This one of the advantages of using JOIN over the IN predicate: SELECT p.name, COUNT(song_id) counter FROM playlist p INNER JOIN playlist_songs s ON p.id = s.playlist_id GROUP BY playlist_id HAVING COUNT(song_id) > 2;

If you group by these columns then you already only get those unique records and then you can use count(*) to get how many duplicates you have. select A,B,C, count(*) from table_name group by A,B,C HAVING count(*) > 1

Select Type, Color, Count(Distinct Location) As UniqueLocations From Table Group By Type, Color Having Count(Distinct Location) > 1 (if you're using MySQL you could use the alias UniqueLocations in your having clause, but on many other systems the aliases are not yet available as the having clause is evaluated before the select clause, in this ...

2017年5月17日 · I was wondering why can't I use alias in a count(*) and reference it in the having clause. For instance: select Store_id as StoreId, count(*) as _count from StoreProduct group by Store_id having _count > 0 Wouldn't work.. But it works if I …

2016年11月21日 · SELECT count(*) FROM ( SELECT COUNT(Genre) AS count FROM movies GROUP BY ID HAVING (count = 4) ) AS x The inner query gets all the movies that have exactly 4 genres, then outer query counts how many rows the inner query returned.